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Volume by shells

  1. Oct 17, 2015 #1
    1. The problem statement, all variables and given/known data
    (a) If the region shown in the figure is rotated about the y-axis to form a solid, use Simpson's Rule with n = 8 to estimate the volume of the solid. (Round your answer to the nearest integer.)

    2. Relevant equations
    delta(x) = b-a/n
    delta(x)/3 [ f(x) + 4f(x)+ 2f(x) + f(x)]


    3. The attempt at a solution
     

    Attached Files:

  2. jcsd
  3. Oct 17, 2015 #2
    my attempt at the solution was

    delta(x) = 10-2/8 = 1

    1/3[ 1+2(1.5)+4(2)+2(2)+4(3)+2(3.5)+4(4)+2(3.5)+1] = 59/3
     
  4. Oct 18, 2015 #3

    SteamKing

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    The formula you have is incorrect for Simpson's First Rule, or at least, it is not written properly.

    Let's stipulate that h = common interval = Δx = (b - a) / n, where a and b represent the x values of the start and finish, respectively, of the x-interval, and n is the number of intervals.

    Then the area under the curve from x = a to x = b is

    A = h * [f(x0) + f(xn) + 2Σ f(x2j) + 4Σ f(x2j-1)]

    The first and last ordinates of the shaded area are both equal to 0, not 1.

    Remember, the problem is asking to find the volume of the solid created by rotating the figure about the y-axis. Calculating the area under the curve is necessary, but not sufficient, to answer this problem.

    To calculate the volume, you'll need to use the Second Theorem of Pappus in addition to Simpson's Rule:

    http://mathworld.wolfram.com/PappussCentroidTheorem.html
     
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