It is necessary to calculate the volume of the coin which has mass 25 kg and how does change its volume when it is necessary to calculate its volume at a depth of 5000m. Compare volume change by pressure with the volume change by pressure with the Volume change by temperature.
volume at surface, M=25kg ρ=m/v
v=1.294 * 10^-3 m³ density of gold ρ= 19320 kg/m³
The Attempt at a Solution
v=1.294 * 10^-3 m³[/B]
I do not know how to calculate the volume at a depth of 5000m but I have pressure at a depth of 5000m.It is 50.3604 MPA. Now I need to find out Temperature using Pressure.