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## Homework Statement

It is necessary to calculate the volume of the coin which has mass 25 kg and how does change its volume when it is necessary to calculate its volume at a depth of 5000m. Compare volume change by pressure with the volume change by pressure with the Volume change by temperature.

## Homework Equations

volume at surface, M=25kg ρ=m/v

v=1.294 * 10^-3 m³ density of gold ρ= 19320 kg/m³

## The Attempt at a Solution

v=1.294 * 10^-3 m³[/B]

I do not know how to calculate the volume at a depth of 5000m but I have pressure at a depth of 5000m.It is 50.3604 MPA. Now I need to find out Temperature using Pressure.