# Volume change due to pressure

## Homework Statement

It is necessary to calculate the volume of the coin which has mass 25 kg and how does change its volume when it is necessary to calculate its volume at a depth of 5000m. Compare volume change by pressure with the volume change by pressure with the Volume change by temperature.

## Homework Equations

volume at surface, M=25kg ρ=m/v
v=1.294 * 10^-3 m³ density of gold ρ= 19320 kg/m³

## The Attempt at a Solution

v=1.294 * 10^-3 m³[/B]
I do not know how to calculate the volume at a depth of 5000m but I have pressure at a depth of 5000m.It is 50.3604 MPA. Now I need to find out Temperature using Pressure.

Chestermiller
Mentor
You are not told the temperature? Then how are you supposed to determine it?

Actually I need the volume at a water depth of 5000m . I can use Boyle's law to calculate Volume and charl's law to calculate Temperatur

I do not how to proceed

Chestermiller
Mentor
Actually I need the volume at a water depth of 5000m . I can use Boyle's law to calculate Volume and charl's law to calculate Temperatur
You are dealing with a solid, not a gas.

Do you know the equation for the volume change of a solid as a function of the temperature change and the pressure change?

Sorry, I don't know

Chestermiller
Mentor
Sorry, I don't know
Do you have a textbook? Otherwise, Google "Bulk compressibility" and "Volumetric thermal expansion."

L=αLT however, I do not know the temperature

Chestermiller
Mentor
L=αLT however, I do not know the temperature
That's the coefficient of linear thermal expansion. The coefficient of volume expansion is 3 x as high.

I guess you need to look up the temperature of the ocean at a depth of 5000 m.

I get it 3 degree Celsius

Sorry, I learnt this formula in structural Mechanics course but I forget it.

here I know only volume and how to proceed?

how can I calculate the volume at a water depth 5000m?

sorry, I get it but How to calculate volume change by pressure?

haruspex