A quartz sphere is 15.5 cm in diameter. What will be its change in volume if it is heated from 40°C to 210°C? Ok so what I did was use the diameter of the sphere and use the volume formula of the sphere and I got 15598.53 cm^3. Then what I did was use this formula [tex] \Delta(V) = \beta V_o\Delta(T) [/tex] knowing this formula I plug in the informationg given in the problem, but the part I don't understand is if its [tex]\Delta(T) [/tex] shouldn't it be the final tamperature minus the initial? Giving me 170 C. I can't do that part I need help.