# Volume Expansion

1. Jan 22, 2006

### ISU20CpreE

A quartz sphere is 15.5 cm in diameter. What will be its change in
volume if it is heated from 40°C to 210°C?
Ok so what I did was use the diameter of the sphere and use the volume formula of the sphere and I got 15598.53 cm^3. Then what I did was use this formula $$\Delta(V) = \beta V_o\Delta(T)$$ knowing this formula I plug in the informationg given in the problem, but the part I don't understand is if its $$\Delta(T)$$ shouldn't it be the final tamperature minus the initial? Giving me 170 C. I can't do that part I need help.

Last edited: Jan 22, 2006
2. Jan 22, 2006

### HallsofIvy

Staff Emeritus
Yes, $$\Delta(T)$$ is the change in temperature, 170 degrees Centigrade. What do you mean you "can't do that part"? Have you looked up $\beta$ for quartz?

3. Jan 22, 2006

### ISU20CpreE

YEs i did but i really cant get the answer the Beta for quartz is 0.000001 i dont get the answer right. What can i do?

4. Jan 22, 2006

### ISU20CpreE

I get 2.65 cm^3 as an answer.

5. Jan 22, 2006

### ISU20CpreE

is this answer corect?