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## Homework Statement

At 19 m below the surface of the sea (den-

sity of 542 kg/m^3), where the temperature is

7 degree C, a diver exhales an air bubble having a

volume of 0.8 cm^3.

If the surface temperature of the sea is 13 degree C,

what is the volume of the bubble immediately

before it breaks the surface? The acceleration

of gravity is 9.8 m/s^3 and the atmospheric

pressure is 1.02 × 105 Pa. Answer in units of

cm^3.

## Homework Equations

[tex]\Delta[/tex]V = [tex]\beta[/tex]Vinitial[tex]\Delta[/tex]T

## The Attempt at a Solution

Vfinal - Vinitial = [tex]\beta[/tex]Vinitial(Tfinal - Tinitial)

Vfinal = [tex]\beta[/tex]Vinital(Tfinal - Tinitial) + Vinitial

= (3400x10^-6)(0.8)(13-7) + 0.8

= 0.81632 cm^3