# Volume Injected into Capillary

#### nayanm

1. Homework Statement

So for an experiment, we injected a small volume of fluid into a capillary (76 micrometer diameter) through a pressure difference and I'm trying to calculate exactly how much was injected.

diameter of capillary = 76e-6 m
height one end was raised above the other = 5.334 cm = 0.05334 m
density of the fluid = .997 g/mL
viscosity of the fluid = 1 g/(m*s) = 0.001 kg/(m*s)
elapsed time during injection = 31 s
capillary length = 78 cm = 0.78 m

2. Homework Equations

The formulas we are given are:
pressure = (density) * (gravitational constant) * (change in height)
volume injected = (pressure * pi * d^4 * t)/(128 * viscosity * capillary length) <-- Poiseuille's Law

3. The Attempt at a Solution

Based on my calculations, I'm getting:

P = (997 kg/m^3)*(9.81 m/s^2)*(0.05334 m) = 521.7 Pa
V = (521.7 Pa)(pi)(76e-6 m)(31s)/(128 * .001 kg/(m*s) * .780 m) = 37.676 m^3

Clearly, we didn't inject anywhere close to that much into a tiny capillary, so where am I going wrong?

Related Introductory Physics Homework Help News on Phys.org

#### haruspex

Homework Helper
Gold Member
2018 Award
diameter of capillary = 76e-6 m
volume injected = (pressure * pi * d^4 * t)/(128 * viscosity * capillary length) <-- Poiseuille's Law
V = (521.7 Pa)(pi)(76e-6 m)(31s)/(128 * .001 kg/(m*s) * .780 m) = 37.676 m^3
Is there something you forgot?

#### nayanm

Is there something you forgot?
Yes. My dignity.

Thank you so much. I can't believe I didn't catch that.