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Homework Help: Volume integral

  1. Oct 6, 2007 #1
    find the volume of the solid resulting when the region enclosed by the curves is revolved around y-axis.

    [tex]x=\sqrt{1+y}[/tex] x=0 y=3

    I am using this integral...


    and I am getting the wrong answer.

    I think it is just arithmetic, but are my bounds correct?

    Last edited: Oct 6, 2007
  2. jcsd
  3. Oct 6, 2007 #2
    Just wondering about the bounds here..
  4. Oct 6, 2007 #3


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    Dearly Missed

    Your bounds&integral look fine to me.
    You should get something like [tex]V=\pi(3+\frac{9}{2}+1-\frac{1}{2})=8\pi[/tex]
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