hi guys. i just need help setting up the integral for the following two problems.(adsbygoogle = window.adsbygoogle || []).push({});

1. find the volume of the solid obtained by rotating the region by the given area about the specified lines.

y= 1/ x^3, y= 0, x=3, x=4 ABOUT x=-3

so i have integral from 3 to 4 of [(-3)^2 - (1/x^3)^2] dx

is that right?

2. find the volume of the solid obtained by rotating the region bounded by the given curves about specified line

y=x^2, x=y^2 about the line x=-3

so i have integral from 0 to 1 of [(3-x^2)^2 - (3-Sqrt(x))^2] dx

is that even close to right?

thank you

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# Volume integration

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