Volume ( is the set up OK?)

  • Thread starter Jbreezy
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  • #1
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Homework Statement



Find the volume obtained by rotating the regon boudned by the given curve about the specified axis

Homework Equations





The Attempt at a Solution



y = secx, y = cosx, 0 <= x < = pi/3

This is what I set up.

V = ∏∫ (secx +1 )^2 - (cosx +1)^2 dx

I said R was secx - (-1) and r is cosx -(-1)
 

Answers and Replies

  • #2
34,688
6,394

Homework Statement



Find the volume obtained by rotating the regon boudned by the given curve about the specified axis

Homework Equations





The Attempt at a Solution



y = secx, y = cosx, 0 <= x < = pi/3

This is what I set up.

V = ∏∫ (secx +1 )^2 - (cosx +1)^2 dx

I said R was secx - (-1) and r is cosx -(-1)
Looks OK, assuming you are rotating the region about the line y = -1, which is info you didn't provide. When you post a problem, remember to include the complete problem statement.
 
  • #3
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Yeah I'm doing it about x = -1. Thanks dude. Sorry.
 
  • #4
arildno
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Why the 1's?
The radii in the cross-sectional disks are specified with the function values.
Thus, your integrand is sec^2(x)-cos^2(x)

I assumed it was about y=0
 
  • #5
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Yeah well that is because I made a mistake in my post and left out that is was about y = -1.
 
  • #6
34,688
6,394
Yeah I'm doing it about x = -1. Thanks dude. Sorry.
Yeah well that is because I made a mistake in my post and left out that is was about y = -1.
Apparently you aren't clear, either.
 
  • #7
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Ha. Lack of sleep
 

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