The base of a solid is the region bounded by y= 2*sqrt(sin(x)) and the x-axis, with x an element of [0, (pi/2)]. Find the volume of the solid, given that the cross sections perpendicular to the x-axis are squares.(adsbygoogle = window.adsbygoogle || []).push({});

Work Shown:

cross sections are squares:

therefore A(x) is not equal to Pi*r^2 rather l^2

therefore A(x)= [sqrt(sin(x)]^2

therefore integral of A(x)dx of x-values from 0 to Pi/2 should provide the answer

I think my approach is wrong and my integral for A(x) dx is wrong as well please help!

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# Homework Help: Volume of a solid bound by region work shown please help!

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