The base of a solid is the region bounded by y= 2*sqrt(sin(x)) and the x-axis, with x an element of [0, (pi/2)]. Find the volume of the solid, given that the cross sections perpendicular to the x-axis are squares.(adsbygoogle = window.adsbygoogle || []).push({});

Work Shown:

cross sections are squares:

therefore A(x) is not equal to Pi*r^2 rather l^2

therefore A(x)= [sqrt(sin(x)]^2

therefore integral of A(x)dx of x-values from 0 to Pi/2 should provide the answer

I think my approach is wrong and my integral for A(x) dx is wrong as well please help!

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Volume of a solid bound by region work shown please help!

**Physics Forums | Science Articles, Homework Help, Discussion**