# Volume of cylinders

1. Jul 31, 2016

### Kirito123

1. The problem statement, all variables and given/known data

2. Relevant equations
V= Pi R2H

3. The attempt at a solution

V = Pi r2h

They gave us the radius and the height (the length can be used as height). They Diameter is 0.9 to find the radius I just divide by 2 = 0.45. So now I find the volume of the cylinder using the formula “V= Pi r2h”. V= 3.14 x 0.2035 x 3.6 = 2.28906 now we divide by 2 since its half a cylinder. So now we do 2.28906 / 2= 1.14453 m3, so the tunnel can hold 1.14453 m3 of air.

(Pretty sure I got this right just want to confirm with others.)

2. Aug 1, 2016

### andrewkirk

Yes that looks right to me.

3. Aug 1, 2016

kk thanks