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Volume of cylinders

  1. Jul 31, 2016 #1
    1. The problem statement, all variables and given/known data
    upload_2016-8-1_0-51-44.png

    2. Relevant equations
    V= Pi R2H

    3. The attempt at a solution

    V = Pi r2h

    They gave us the radius and the height (the length can be used as height). They Diameter is 0.9 to find the radius I just divide by 2 = 0.45. So now I find the volume of the cylinder using the formula “V= Pi r2h”. V= 3.14 x 0.2035 x 3.6 = 2.28906 now we divide by 2 since its half a cylinder. So now we do 2.28906 / 2= 1.14453 m3, so the tunnel can hold 1.14453 m3 of air.



    (Pretty sure I got this right just want to confirm with others.)
     
  2. jcsd
  3. Aug 1, 2016 #2

    andrewkirk

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    Yes that looks right to me.
     
  4. Aug 1, 2016 #3
    kk thanks
     
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