- #1
WayBehind
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I know this has been answered in another thread, but it still isn't entirely clear to me. This particular section in class is giving me some major problems and I'm hoping someone can shed some light on things. This is probably one of the easier problems in this assignment and I'm hoping if I can figure it out then the rest will fall into place.
I thought spherical coordinates would be appropriate here, but I can't seem to find a correct answer.
b]1. Homework Statement [/b]
FInd the volume of the ellipsoid [tex]x^2 + y^2 + 4 z^2 = 100[/tex]
if I convert to spherical coordinates, I can reduce the following:
[tex] \rho^2sin^2\phi cos^2\theta + \rho^2sin^2\phi sin^2\theta + 4\rho^2cos^2\phi = 100 [/tex]
to
[tex] \rho=\sqrt{20} [/tex]
So I'm trying to set up my equation and get:
[tex]
\int_{0}^{2\pi}\int_{0}^{?}\int_{0}^{\sqrt{20}} d\rho d\phi d\theta
[/tex]
I'm fairly certain I'm not really on the right track, if someone could confirm that...
How do I find the value of [tex]\phi[/tex]?
And I'm not even really sure how to find the equation, although I'm guessing I am just being dense.
Any help would be appreciated.
I thought spherical coordinates would be appropriate here, but I can't seem to find a correct answer.
b]1. Homework Statement [/b]
FInd the volume of the ellipsoid [tex]x^2 + y^2 + 4 z^2 = 100[/tex]
Homework Equations
The Attempt at a Solution
if I convert to spherical coordinates, I can reduce the following:
[tex] \rho^2sin^2\phi cos^2\theta + \rho^2sin^2\phi sin^2\theta + 4\rho^2cos^2\phi = 100 [/tex]
to
[tex] \rho=\sqrt{20} [/tex]
So I'm trying to set up my equation and get:
[tex]
\int_{0}^{2\pi}\int_{0}^{?}\int_{0}^{\sqrt{20}} d\rho d\phi d\theta
[/tex]
I'm fairly certain I'm not really on the right track, if someone could confirm that...
How do I find the value of [tex]\phi[/tex]?
And I'm not even really sure how to find the equation, although I'm guessing I am just being dense.
Any help would be appreciated.