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## Homework Statement

Calculate the volume required to hydrogenate 50g of trans-carveol at STP.

## Homework Equations

PV=nRT

m=152g

## The Attempt at a Solution

I think I might have this one but just for clarification if I'm missing something. The amount of moles is 0.329 using the amount of carveol given and the molecular mass. So plugging in:

V=(0.329)(8.315)(298)/1

= 815L

Now, there are two double bonds in trans-carveol, so we need double the amount of hydrogen to hydrogenate the double bonds. So would it just be 815L x 2 = 1630L needed?