1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Volume of revolution

  1. Jan 23, 2007 #1
    The question I need to solve for an assignment is as follows:
    Find the volume of the solid that is obtained by revolving the region R around the x-axis.

    I figured that the volume would just be the integral of pi R^2 dx, so that would just be pi R^2 x, but that is not the answer. I suspect I am misinterpreting the question.
     
  2. jcsd
  3. Jan 23, 2007 #2

    cristo

    User Avatar
    Staff Emeritus
    Science Advisor

    Well, R is probably a function of x. If you write the question, as stated, then we'll be more able to help you!
     
  4. Jan 23, 2007 #3
    My problem is that that is the problem as stated. It doesn't give a function in terms of x.
     
  5. Jan 23, 2007 #4
    Ah nevermind, I found out that the question was referring to an area already found in a previous question.
     
  6. Jan 23, 2007 #5

    Gib Z

    User Avatar
    Homework Helper

    Yes, and if it didn't specify the function, it would be [tex]\pi\int^b_a R^2 dx[/tex] anyway, where R is the closed interval (a,b).
     
  7. Jan 24, 2007 #6

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    Even that wouldn't make sense! If R is an interval it is not a number! I think both you and ductape are confusing the interval R with "radius" R.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Volume of revolution
  1. Volume of Revolution (Replies: 2)

  2. Volume of revolution (Replies: 2)

  3. Volume by revolution (Replies: 4)

  4. Volumes of revolution (Replies: 7)

  5. Volume of revolution (Replies: 10)

Loading...