How do you find the volume of the solid obtained by rotating the region bounded by the given curves about the specified lines?
I keep getting a negative number and I"m becoming so frustrated! 11pi/30 is the answer in the textbook. Thank you so very much in advance!
The Attempt at a Solution
pi[(1-x^2)^2 - (1-x^(1/2))^2)]
pi[1-2x^2+x^4-1+2x^(1/2)-x) between x=0 and x= 1
pi[(1/5x)^5-(2/3)x^3 + (2/3)x^(3/2)-(1/2)x^2]
pi((2/10)-(5/10)) = -3pi/10???????
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