Find the volume of the solid in the first octant of xyz space, bounded below by the coordinate axes and the unity circle and bounded above by z = 8xy.(adsbygoogle = window.adsbygoogle || []).push({});

A) 1/2 B) 1 C) 2 D) 4 E) 8

I know definitely volume will be the double integral of 8xy dy dx.

I think my limits of integration for the inner integral should be -sqrt(1-x^2) to sqrt(1-x^2). Since we are looking at the unit circle ( x^2 + y^2 = 1)

The outer integral limits should just be from -1 to 1?

Is this correct?

When I do the inner integral I get 4x(y^2) evaluated between -sqrt(1-x^2) to sqrt(1-x^2) but this looks like it just gives me 0 when I do the inner integral....

4x(sqrt(1-x^2))^2 - 4x(-sqrt(1-x^2))^2

Can someone help me and tell me if I am doing something wrong. I think i am

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# Homework Help: Volume of Solid in R3

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