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## Homework Statement

Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis:

x+3=4y-y^2

x=0

About x-axis

## Homework Equations

## The Attempt at a Solution

I tried solving x+3=4y-y^2 for y, but I can't get it even though it seems simple.

*Edit*

Can someone check if I set up this integral correctly (for a different problem)?

Find volume of region bounded by given curve and rotated around given axis:

y=x^3

y=8

x=0

Rotate about x=2

Integral from 0 to 8 of: pi(2-0)^2 - pi(2-x^1/3)^2 dy

thanks

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