Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis:
The Attempt at a Solution
I tried solving x+3=4y-y^2 for y, but I can't get it even though it seems simple.
Can someone check if I set up this integral correctly (for a different problem)?
Find volume of region bounded by given curve and rotated around given axis:
Rotate about x=2
Integral from 0 to 8 of: pi(2-0)^2 - pi(2-x^1/3)^2 dy