f(x) =e^x and g(x)= ln(x)
Find the volume of the solid generated when the region enclosed by the graphs of f and g between x=1/2 and x=1 is revolved about the line y=4
v= pi* integral( f(x)^2 - g(x)^2 dx)
The Attempt at a Solution
SO for the part about the volume
I set up my integral as V= pi* integral ( (4-e^x)^2 - (4- ln(x))^2 dx) from 1/2 to 1 and get around -23. Am I right ? should it be 4-e^x or e^x-4 ?