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Volume spherical coordinates

  1. May 13, 2010 #1
    Say I have a solid given using polar coordinates
    I want to compute its volume.

    We know that when switching from cartesian to polar, dV becomes [tex]\rho^{2}\sin\phi d\rho d\theta d\phi[/tex]

    But I am not converting from cartesian to polar, I am already in polar coordinates.

    do I still have to carry the [tex]\rho^{2}\sin\phi[/tex] that comes from the dV conversion formula?
  2. jcsd
  3. May 13, 2010 #2
    Yes, you do. That formula for dV is the volume element in spherical coordinates, whether you're converting into spherical coordinates or staying in spherical coordinates.
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