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- Thread starter flash9286
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- #2

arildno

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Set up the equations you used!

- #3

HallsofIvy

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How about showing us exactly what you integrated and how you got those answers?

- #4

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The second one, which I'm not sure about, would be same b and a, on the integral pi*(9-(9-x^2))^2

- #5

HallsofIvy

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When you rotate around the y-axis, your "disks" will be moving up the y axis. The radius of each disk will be x as a function of y and their "thickness" is dy.

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- #7

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[tex] \int_{0}^{3} pi*9^2-(pi*(9-9+x^2)^ dx [/tex] is what the second integral maybe?

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