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Volume using molarity

  1. Jul 14, 2014 #1

    RJLiberator

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    Question: What volume of a 0.835 M solution of Na2SO4 do you have if there are 0.0534 mol of Na+ present in the solution?

    What I did: Since we have 0.0534 moles of Na+ ions in the Na2SO4 molecule, I used that for the equation. Since 0.0534 moles is in a 1:1 ratio with Na2SO4 I can conclude we have 0.0534 moles of Na2SO4.

    M = Moles/Volume
    0.835M = 0.0534moles of Na2SO4/V
    Solving, I get 6.40x10^-2L

    Is my reasoning correct?
     
  2. jcsd
  3. Jul 14, 2014 #2

    Simon Bridge

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    Well that is the definition of molarity you used there... so you reasoned:

    M=n/V => V=n/M plug numbers in.
    No worries.
     
  4. Jul 14, 2014 #3

    Borek

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    Can you? Is it really 1:1?
     
  5. Jul 14, 2014 #4

    RJLiberator

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    Ah, prior to my test I spoke with my professor and it appears that I can do no such thing. There is 2 Na ions and 1 So4 ions so it is actually a 2 to 1 ratio. I will work this out when I get home tonight. :)

    Thank you.
     
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