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Volume using the shell method

  1. Jun 19, 2009 #1
    1. The problem statement, all variables and given/known data

    Use the shell method to find the volumes of the solid generated by revolving the regions bounded by the curves and lines.

    x=2y-y2, x=0

    2. Relevant equations

    The shell method is of the format: [tex]V = 2 \pi\int x * height dx[/tex]


    3. The attempt at a solution

    I cannot picture the problem (not sure exactly how to graph it)
     
  2. jcsd
  3. Jun 19, 2009 #2

    Dick

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    x=2y-y^2 is a parabola and x=0 is a line. What's the problem with graphing them? Where do they intersect? And what what axis are you going to rotate the region around?
     
  4. Jun 19, 2009 #3
    rotating around the x-axis


    how can I tell its a parabola?
     
  5. Jun 19, 2009 #4
    A usual parabola is given by [itex]y = ax^2 + bx + c[/itex]. In this case, we have [itex]x = ay^2 + by + c[/itex]. The two are much the same really, except that in the second case, the parabola is 'on it's side'.

    It is actually two square roots, pasted together though. You can see this by solving the equation for y, resulting in your usual "y = f(x)" graph. For general a, b, c:
    [tex]y = \frac{-b \pm \sqrt{b^2 - 4ac + 4ax} }{2a}[/tex]
    (Two equations, one for + and one for -!)

    If you graph these, we get (using a = 1, b = 2, c = -1 for example):
    sqrz8o.jpg
    (The two don't meet in the middle exactly because Maple has trouble graphic them there.)


    If you really can't figure out the shape of a curve, why not simply try to draw a few easy points on paper? Like (0,0) or (0,1), (1,0) etc... You will most likely recognize a familiar shape from that, and you can then go on and analyze the curve equation further.
     
    Last edited: Jun 19, 2009
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