- #1

- 30

- 0

## Main Question or Discussion Point

Find the volume of the solid formed by rotating the region inside the first quadrant enclosed by

y=x^2

y=2x

about the x-axis.

So i used intergral 0 to 2 (2x-x^2)^2 dx

this is wat i got....

pi*(((2^5)/5)-(4(2^4)/4)+(4(2^3)/3))

its wrong so wat did i do wrong?

y=x^2

y=2x

about the x-axis.

So i used intergral 0 to 2 (2x-x^2)^2 dx

this is wat i got....

pi*(((2^5)/5)-(4(2^4)/4)+(4(2^3)/3))

its wrong so wat did i do wrong?