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Volumes of revolution

  1. May 31, 2009 #1
    so i have y = 1/sqroot(3x+2)

    find volume when rotated around x, regions are x=2 and x=0

    equation needed: V= integral Pi*y^2*dx


    i do intergral pi* (1/sqroot(3x+2))^2 * dx

    so i get pi integral 1/(3x+2) dx

    so how do i integrate 1/sqroot(3x+2) ?

    can someone take me though it , because i know theres meant to be a constant near the ln, but i don't know how to find it.

    thanks, sorry if it's explained bad
  2. jcsd
  3. May 31, 2009 #2


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    Homework Helper

    Try putting u=3x+2
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