(adsbygoogle = window.adsbygoogle || []).push({}); Find the volume of the solid generated by revolving the region bounded by [tex]y = 2x - x^2[/tex] and y = x about the line x = 1

Ok, so I can solve this if it were revolved around the y-axis, it would be: [tex]\pi \int_0^1 (x)^2 - (2x - x^2)^2 dy[/tex]

If I have to revolve it around x = 1, what do I need to change with the equation?

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# Volumes of solid revolution

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