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Volumetric Charge Density

  • Thread starter satchmo05
  • Start date
  • #1
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Homework Statement


If the Earth's surface was charged to QTOTAL = 13548.3 [C] by removing all of the electrons from a volume of soil, how large would this volume be? Assume electron density of soil = 7e23 [cm-3].

Homework Equations


Volumetric charge density pv = QTOTAL/volume of soil.

Electron density is = # of electrons per unit volume.

The Attempt at a Solution


By rearranging the volumetric charge density formula, I can gather that QTOTAL / pv. Rearranging the second formula, I can get volume equal to #electrons/electron density. In a general sense, density is equal to mass/volume. I could solve for volume easily here, knowing the mass of an electron. But then, how is charge involved? How do I get the volume of soil, given the amount of charge that was removed from this volume?

Thank you for the help!
 

Answers and Replies

  • #2
ehild
Homework Helper
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No mass is involved in this problem. You have charge, charged particles (electrons) and their density. You know the charge of an electron. Knowing the electron density (number of electrons in 1 cm-3), calculate the charge density. From the total charge and charge density, you get the volume.

ehild
 

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