If the Earth's surface was charged to QTOTAL = 13548.3 [C] by removing all of the electrons from a volume of soil, how large would this volume be? Assume electron density of soil = 7e23 [cm-3].
Volumetric charge density pv = QTOTAL/volume of soil.
Electron density is = # of electrons per unit volume.
The Attempt at a Solution
By rearranging the volumetric charge density formula, I can gather that QTOTAL / pv. Rearranging the second formula, I can get volume equal to #electrons/electron density. In a general sense, density is equal to mass/volume. I could solve for volume easily here, knowing the mass of an electron. But then, how is charge involved? How do I get the volume of soil, given the amount of charge that was removed from this volume?
Thank you for the help!