- #1

- 60

- 0

To find the wall shear stress, i used τ=μ.du/dy = (2.9x10^-3)(0.5/0.012) = 0.121Pa

The answer is 0.968Pa, where am i going wrong?

thanks

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- Thread starter Anony-mouse
- Start date

- #1

- 60

- 0

To find the wall shear stress, i used τ=μ.du/dy = (2.9x10^-3)(0.5/0.012) = 0.121Pa

The answer is 0.968Pa, where am i going wrong?

thanks

- #2

- 783

- 9

What are the units of density?

- #3

- 783

- 9

- #4

- 60

- 0

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