1. The problem statement, all variables and given/known data "In part 2 of the lab you will be firing a water balloon over a tall fence, aiming to hit a target." The fence is 3 meters high. You may fire the balloon from anywhere behind the fence, up to 4 meters away from it: the target will be 20 meters away. Find the angle to shoot the balloon and the stretching distance. There are multiple correct answers. horizontal distance=s = 20 to 24 meters mass= .25kg Spring constant= k= 336.4 spring stretching distance= x = 0 to 25 centimeters theta=? 2. Relevant equations PE + W = KE PE=.5k x^2 w = Fk * s Fk = k*x KE= .5mv^2 3. The attempt at a solution Assuming we use all 24 meters .5(336.4)(x^2) + 24(336.4)(x) = .5(.25)v^2 v= sqrt(2691.2((x^2)/2)+24x) We're lost after this. Even plugging in a value for x gives us a very large velocity. For example plugging x=.2 gives a velocity of ~113 m/s. This doesn't seem realistic.