• Support PF! Buy your school textbooks, materials and every day products via PF Here!

Water density

  • Thread starter Swatch
  • Start date
89
0
At the bottom of the ocean at 10.92 km the pressure is 1.16*10^8 pa.
If the pressure is calculated ignoring the change of density the pressure is 1.10*10^8 pa
I have to calculate the water density at the bottom using the compressibility and the actual pressure.

Since k= - Delta V/Vo*DeltaP
DeltaP*k= - DeltaV/Vo and V=m/rho
DeltaP*k=-(rho1-rho2)/rho2 where rho1 and rho2 are the water density at the surface and at the bottom respectively.
I end up with:
rho2=-rho1/(DeltaP*k -1)

From this I get rho2 as 1033 pa but I should get 1080 pa

Could someone please give me a hint to what I am doing wrong?


Thanks.
 

FredGarvin

Science Advisor
5,050
6
I don't recognize your form of the definition of the bulk modulus. It should be in the form of:

[tex]k = -V \frac{\Delta P}{\Delta V}[/tex]

I am still working through the units. You should end up with kg/m^3 for density, not Pa. Pascals are units of pressure.
 

FredGarvin

Science Advisor
5,050
6
OK. I finally went thru it. First, it will depend on what values you are using for the density of water at the surface and for the bulk modulus.

After substituting [tex]\rho = \frac{m}{V}[/tex] in the above definition and some algebra, I end up with:

[tex]k = - \frac{\Delta P}{\frac{\rho_1}{\rho_2} - 1}[/tex]

Like I said, it depends on what you use for k and [tex]\rho[/tex] at the surface. I used k = 2.2x10^9 and [tex]\rho_1[/tex] = 1000 kg/m^3 and ended up with a result of [tex]\rho_2[/tex] = 1055.6 kg/m^3 which is pretty close to what you say numerically you should get.
 
Last edited:
89
0
I don't understand.
According to my text book the bulk modulus is -DeltaP*V/DeltaV

The compressibility, k is the reciprocal of the bulk modulus and so is
k=-DeltaV/V*DeltaP
 

FredGarvin

Science Advisor
5,050
6
Ahh. I see. I'm used to seeing "k" for bulk modulus and "c" for compressibility. It doesn't really matter though. It should all work out in the end. If you solve my equation for bulk modulus for [tex]\rho_2[/tex] and invert it, you will get the same result that you have in your original post.

Also, it might help if you were to present the equation as: k = -DeltaV/(V*DeltaP). I am admittedly horrible when having to do orders of operation, so I like to see parentheses.

What values did you use for the density at sea level and for compressibility? Did you see my comment about the units you ended up with?
 

Related Threads for: Water density

  • Posted
Replies
3
Views
8K
  • Posted
Replies
13
Views
8K
  • Posted
Replies
4
Views
826
  • Posted
Replies
3
Views
2K
Replies
5
Views
4K
  • Posted
Replies
4
Views
9K
  • Posted
Replies
11
Views
7K
  • Posted
Replies
3
Views
20K

Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving
Top