# Water density

Swatch
At the bottom of the ocean at 10.92 km the pressure is 1.16*10^8 pa.
If the pressure is calculated ignoring the change of density the pressure is 1.10*10^8 pa
I have to calculate the water density at the bottom using the compressibility and the actual pressure.

Since k= - Delta V/Vo*DeltaP
DeltaP*k= - DeltaV/Vo and V=m/rho
DeltaP*k=-(rho1-rho2)/rho2 where rho1 and rho2 are the water density at the surface and at the bottom respectively.
I end up with:
rho2=-rho1/(DeltaP*k -1)

From this I get rho2 as 1033 pa but I should get 1080 pa

Could someone please give me a hint to what I am doing wrong?

Thanks.

I don't recognize your form of the definition of the bulk modulus. It should be in the form of:

$$k = -V \frac{\Delta P}{\Delta V}$$

I am still working through the units. You should end up with kg/m^3 for density, not Pa. Pascals are units of pressure.

OK. I finally went thru it. First, it will depend on what values you are using for the density of water at the surface and for the bulk modulus.

After substituting $$\rho = \frac{m}{V}$$ in the above definition and some algebra, I end up with:

$$k = - \frac{\Delta P}{\frac{\rho_1}{\rho_2} - 1}$$

Like I said, it depends on what you use for k and $$\rho$$ at the surface. I used k = 2.2x10^9 and $$\rho_1$$ = 1000 kg/m^3 and ended up with a result of $$\rho_2$$ = 1055.6 kg/m^3 which is pretty close to what you say numerically you should get.

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Swatch
I don't understand.
According to my textbook the bulk modulus is -DeltaP*V/DeltaV

The compressibility, k is the reciprocal of the bulk modulus and so is
k=-DeltaV/V*DeltaP

Ahh. I see. I'm used to seeing "k" for bulk modulus and "c" for compressibility. It doesn't really matter though. It should all work out in the end. If you solve my equation for bulk modulus for $$\rho_2$$ and invert it, you will get the same result that you have in your original post.