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Water displacement problem.

  1. Sep 13, 2009 #1
    1. The problem statement, all variables and given/known data
    Calculate the volume of water, in milliliters, that would be displaced by 1.82 grams of cobalt, when cobalt's density is 8.9 g mL^-1.


    2. Relevant equations
    Density = m/v
    Volume = m/d



    3. The attempt at a solution
    volume = m/d
    Volume= 1.82 g/8.9 g mL^-1
    Volume = 0.204 mL^-1?

    I'm honestly stumped. Hopefully someone has some sort of idea of how to solve this.
     
  2. jcsd
  3. Sep 13, 2009 #2
    I think your correct :). Because the object is totally submerged (density of Cobalt is greater than that of water), it displaces a volume in liquid equal to the volume of itself.

    For future reference, the mass of liquid displaced is also equal to the mass of the object itself.
     
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