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Water drain rate from barrel

  1. Sep 12, 2005 #1
    I've got a math problem, thats way over my head, here it is.
    Figurativly I have a 33 gallon barrel and it has a one inch hole in the bottom, if the barrel is full of water, how many gallons would escape a minute, the top is open, I need to know to figure out how much water being pumped in would be needed to keep the barrel full?
    If it turns out to be a simple answer, what would the result be if it was a two inch hole?
  2. jcsd
  3. Sep 13, 2005 #2


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    You have to put in the same amount as is leaving.
    Unless you know the depth (under water) of the hole,
    you can't even start (the speed is 0 if depth is 0).
  4. Sep 13, 2005 #3
    Not sure what your saying , but the barrel is full of water when the spigot at the bottom is opened, and the extra water is being fed into it at the top, at this same rate, from another source.
  5. Sep 13, 2005 #4

    Although I can't figure it out, I've seen in these forums that it can be calculted how long it would take a cubic mile by a cubic mile container of water to finally drain out of a one inch hole, is this a different mindset?
  6. Sep 14, 2005 #5


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    It the barrel remain full you need height of the barrel to find the velocity of water draind given by v = sq.rt.(2gh)
    then the volume flow rate will be A*v should be equal to the water to be pumped in where A is the cross-section area of the hole.
  7. Sep 14, 2005 #6
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