- #1

uhuge

- 7

- 0

I am verifying my answer with some really bright people. You

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- Thread starter uhuge
- Start date

- #1

uhuge

- 7

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I am verifying my answer with some really bright people. You

- #2

Tide

Science Advisor

Homework Helper

- 3,089

- 0

I am verifying my answer

Why don't you at least tell us how you arrived at your answer? :)

- #3

uhuge

- 7

- 0

Realizing that flow rate is equal to velocity time area of the opening, we can solve for time to drain a certain amount of the tank. The problem is h (height of the fluid) is constantly changing so the formula must be continueously recalculated.

I have a number, I just want to see how close I actually am with my estimation.

- #4

Tide

Science Advisor

Homework Helper

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[tex]t = \frac {2A}{a} \sqrt {\frac {H}{2g}}[/tex]

where A is the cross sectional area of the water, a is the area of the opening and H is the starting height of the water. Is that consistent with your analysis?

- #5

uhuge

- 7

- 0

- #6

uhuge

- 7

- 0

I think i made a mistake in that when I do your calculations I get 21005.32 years. Is this what you get?

- #7

Tide

Science Advisor

Homework Helper

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uhuge,

I got about 2300 years when I used my formula. Check your units carefully.

I got about 2300 years when I used my formula. Check your units carefully.

- #8

Dr.Brain

- 538

- 2

BJ

- #9

quark

- 231

- 1

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