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I am verifying my answer with some really bright people. You

- Thread starter uhuge
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- #1

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I am verifying my answer with some really bright people. You

- #2

Tide

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Why don't you at least tell us how you arrived at your answer? :)I am verifying my answer

- #3

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Realizing that flow rate is equal to velocity time area of the opening, we can solve for time to drain a certain amount of the tank. The problem is h (height of the fluid) is constantly changing so the formula must be continueously recalculated.

I have a number, I just want to see how close I actually am with my estimation.

- #4

Tide

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[tex]t = \frac {2A}{a} \sqrt {\frac {H}{2g}}[/tex]

where A is the cross sectional area of the water, a is the area of the opening and H is the starting height of the water. Is that consistent with your analysis?

- #5

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- #6

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I think i made a mistake in that when I do your calculations I get 21005.32 years. Is this what you get?

- #7

Tide

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uhuge,

I got about 2300 years when I used my formula. Check your units carefully.

I got about 2300 years when I used my formula. Check your units carefully.

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BJ

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