Water flows steadily from an open tank as shown in the figure.The elevation of point 1 is 10.0 meters, and the elevation of points 2 and 3 is 2.00 meters. The cross-sectional area at point 2 is 0.0480 square meters; at point 3, where the water is discharged, it is 0.0160 square meters. The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe. Assuming that Bernoulli's equation applies, compute the discharge rate . Express your answer in cubic meters per second. I have no idea how to approach this...sorry...any help i can get would be amazing!
Write out what you know. Then write out what you need to find. Then write down the equations you are using (in this case Bernoulli's Equation and the definition for volume flow rate) What other terms of the equation do you need to find in order to solve the problem?