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Water Flowing from a Tank

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Homework Statement



Link to picture: http://session.masteringphysics.com/problemAsset/1011222/12/yf_Figure_14_41.jpg

Water flows steadily from an open tank as shown in the figure. The elevation of point 1 is 10.0 m, and the elevation of points 2 and 3 is 2.00 m. The cross-sectional area at point 2 is 4.80×10−2 m^2; at point 3, where the water is discharged, it is 1.60×10−2 m^2. The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe.


Homework Equations



Delta V = (A)(v)( Delta t)

A1(v)1=A2(v)2

The Attempt at a Solution



I can't figure this out.

To know the velocity of at point 3, dont you have to know the area of the main tank, to get the velocity at point 2, and then point 3?

The Area of point 2 and 3 is given, but no velocity, so what am I missing??

Homework Statement





Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
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So it ask:

Assuming that Bernoulli's equation applies, compute the volume of water DeltaV that flows across the exit of the pipe in 1.00 {\rm s}. In other words, find the discharge rate \Delta V/\Delta t.
 

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