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Introductory Physics Homework Help
Water flows from a compressed tank
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[QUOTE="Karol, post: 4963061, member: 20512"] [h2]Homework Statement [/h2] A tank of height 3.6[m] and closed at the top is filled with water to height 3[m], see drawing. the pressure P[SUB]1[/SUB] above the water is 1.055[kgf/cm[SUP]2[/SUP]. A pipe is coming out from the bottom and the opening is 1.5[m] above the ground. what is the water's velocity out of the pipe when the water in the tank is at 3[m] and at 2.4[m]. neglect friction and assume the air expands isothermally. [h2]Homework Equations[/h2] Bernoully equation: ##\frac{v^2}{2}+gz+\frac{P}{ρ}=Const## z=height, ρ=specific mass[kg/m[SUP]3[/SUP] Atmospheric pressure: 101,325[pa] The specific mass of water=1000[kg/m[SUP]3[/SUP]] In an isothermic process: ##P_1V_1=P_2V_2## [h2]The Attempt at a Solution[/h2] The pressure above the water in pascals: $$1.055\left[\frac{kgf}{cm^2}\right]=10.55\left[\frac{N}{cm^2}\right]=105,500\left[\frac{N}{m^2}=pa\right]$$ The left side is the outlet of the pipe. the zero for height is the pipe's exit: $$\frac{v^2}{2}+\frac{101,325}{1000}=1.5\cdot 10+\frac{105,500}{1000}\rightarrow v=6.2\left[\frac{m}{sec}\right]$$ When the water lowers to 2.4[m] the pressure drops (A=base area of tank): $$105,500\cdot A\cdot 0.6=P_2\cdot A\cdot 1.2\rightarrow P_2=52,570[pa]$$ $$\frac{v^2}{2}+\frac{101,325}{1000}=0.9\cdot 10+\frac{52,570}{1000}$$ It gives a negative sign, does it mean the water flows in? [/QUOTE]
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Introductory Physics Homework Help
Water flows from a compressed tank
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