Water force through weight

  • #1
gerrywelshman
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Hi All,
If I have a tank 1meter dia 5metres height and a tank 200mm dia (1/5 size ) 5metres high
and I have a horizontal tap at the bottom of each. when I open the taps will I get more distance
of water from the bigger tank.
 

Answers and Replies

  • #2
BiGyElLoWhAt
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Have you tried figuring out the pressure? (Force/ unit area) If the pressures are the same, then you will get the same, if one is larger, it will shoot the water further out of the tap.
 
  • #3
gerrywelshman
2
0
Hi BiGyElLoWhAt, (some handle that)
I have been interested in a design feature.
Thanks for clarifying a discussion I've had lately .
I had been told the water would shoot out the same distance.
 
  • #4
BiGyElLoWhAt
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That very well may be, but I wouldn't be so sure without making the calculation. If you look at a cross section of the water, then the pressure on the water below it would be the weight of the water above that cross section divided by the area (pi*r^2).

If you're looking at something of the order of 200mm diameter, then the adhesive properties of water would become non-negligible, in my opinion.
 
  • #5
pbuk
Science Advisor
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Have you tried figuring out the pressure? (Force/ unit area) If the pressures are the same, then you will get the same, if one is larger, it will shoot the water further out of the tap.
That's a helpful answer.

If you look at a cross section of the water, then the pressure on the water below it would be the weight of the water above that cross section divided by the area (pi*r^2).
And that's not. Pressure in a tank is only dependent on depth, not the size or shape of the tank.

If you're looking at something of the order of 200mm diameter, then the adhesive properties of water would become non-negligible, in my opinion.
And that's just irrelevant.

Perhaps the best answer is: look up Torricelli's Law.
 
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  • #6
BiGyElLoWhAt
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...Pressure in a tank is only dependent on depth, not the size or shape of the tank...
I understand that the cross section divides out from the volume, giving a depth dependant function. My purpose was to get the OP to do the calculation and figure it out. Good Job.
 
  • #7
BiGyElLoWhAt
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Also, adhesion is not irrelevant for small enough containers.
 
  • #8
DaveC426913
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Also, adhesion is not irrelevant for small enough containers.
That's an 8-inch diameter cylinder. Water adhesion might be relevant to the OP's education, but surely not to this application.
 
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  • #9
BiGyElLoWhAt
Gold Member
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That's an 8-inch diameter cylinder. Water adhesion might be relevant to the OP's education, but surely not to this application.
Very true. Not sure how I grossly underestimated that, but...
 

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