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Homework Statement
Suppose the water fountain in fountain hills, Arizona, rises 150ft above the lake. Neglecting wind effects and minor losses, determine the velocity at which the water is ejected
yes, i tried using this formula, but i dont know if its rightdid you make an attempt at this problem?
yes thats what i meant. is the steps i used in the above right?I assume what you mean is that water is squirted directly upward so it reaches a peak 150 ft above the jet where it exited. If that is the situation, it is the same as shooting a projectile straight up.
Nope, the initial velocity is not right. The water rises up to 150 ft. What does this tell you?yes, i tried using this formula, but i dont know if its right
V^2 = Vo^2 + 2AD
A = 9.8m/s^2
V^2 = 0^2 + 2(9.8)D
V^2 = 19.6D
yes, i tried using this formula, but i dont know if its right
V^2 = Vo^2 + 2AD
A = 9.8m/s^2
V^2 = 0^2 + 2(9.8)D
V^2 = 19.6D
So it should be like thisNope, the initial velocity is not right. The water rises up to 150 ft. What does this tell you?
..and also, the given unit is ft. Then, g = 32 ft/s/s
Well, gravity drags the "projectile of the water" down. Consider throwing up the ball for example. If you toss the ball, then you exert the initial velocity v_0. At the highest point (or at the max height), the ball stops rising. That means v = 0 ft/s or v_f = 0 ft/s. After that time, the ball falls down due to gravity.So it should be like this
V^2 = Vo^2 + 2AD
A = 32 ft/s
V^2 = Vo^2 + 2(32)150
then what is the value fo V^2