# Water heater warms 137 kg water from 20C to 45 C in 16 min. - Heating element resist?

## Homework Statement

A well-insulated electric water heater warms 137 kg of water from 20°C to 45.0°C in 16.0 min. Find the resistance of its heating element, which is connected across 220-V potential difference.

R=V/I

## The Attempt at a Solution

Not sure how to approach this one. Should I refer to a calorimetry approach along with electrical relations? How might I start this one?

Any help/hints would be greatly appreciated.

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There is also an equation that relates the power to the voltage V and the resistance R.
On the other hand, you should be able to calculate the power from the given data.

Gotcha. Thanks for the hint. Looks like Q = mc delta T works great for calculating necessary heat to heat the water while v squared over R multiplied by time (in seconds) equals the heat generated by potential and resistance over time.

I appreciate your time in providing the hint.