1. A fire hose exerts a force on the person holding it. This is because the water accelerates as it goes from the hose through the nozzle. How much force is required to hold a 7.5 cm diameter hose delivering 470 L/min through a 0.80 cm diameter nozzle? 2. Relevant equations I think we need to use the continuity eqn: A1V1 = A2V2 = Q and the Bernoulli eqn: P + (rho)gh + 1/2 (rho)v^2 = constant 3. The attempt at a solution Using the continuity equation, I found the velocities in the nozzle and in the hose V1 (in nozzle) = 38.97 m/s V2 (in hose) = 1.77 m/s Then I used the bernoulli equation to solve for the pressure in the hose. P1 = P2 + 1/2 (rho)[(v2)^2-(v1)^2] with P2 = 1.0*10^5 Pa P1 = 857830.4646 Pa Then I said P = F/A F = PA = 857830.4646 Pa(Area of hose) F = 3789.8 N But this is the wrong answer - I wonder if my logic itself is faulty?