- #1
member 428835
Hi PF!
Suppose I have a square tank of water. If I drive the tank of water such that it's height as a function of time is ##h(t) = \cos(t)##, ignoring gravity, is this the same thing as saying the tank is holding still but the pressure field is changing as ##p(t)=\cos(t)##?
Suppose I have a square tank of water. If I drive the tank of water such that it's height as a function of time is ##h(t) = \cos(t)##, ignoring gravity, is this the same thing as saying the tank is holding still but the pressure field is changing as ##p(t)=\cos(t)##?