Water in capillary tube

  • Thread starter vissh
  • Start date
  • #1
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heya :D

Homework Statement


(Q)Water rises in a vertical capillary tube upto a length of 10 cm. If the tube is inclined at 45 degrees, the length of water risen in the tube will be
<a>10 cm <b>10/(2)1/2 <c>10(2)1/2 <d>None of these

Homework Equations


Height raised in capillary, h = [2S(cosA)]/[rpg]
--where S is surface tension, A is the contact angle , r is the radius of capillary , p is the density of liquid and g is acceleration due to gravity

The Attempt at a Solution


I know this above formula for height of liquid when the capillary is kept vertical .But don't know how to use it for the inclined capillary.
Can any1 help me out :)
Thanks for reading ^.^
 

Answers and Replies

  • #2
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Think about this: To keep the pressure at a height 'h' from the ground equal, the level of mercury changes when the tube is inclined. Think about pressure at a fixed point in both the cases :wink:
 

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