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## Homework Statement

(Q)Water rises in a vertical capillary tube upto a length of 10 cm. If the tube is inclined at 45 degrees, the length of water risen in the tube will be

<a>10 cm <b>10/(2)

^{1/2}<c>10(2)

^{1/2}<d>None of these

## Homework Equations

Height raised in capillary, h = [2S(cosA)]/[rpg]

--where S is surface tension, A is the contact angle , r is the radius of capillary , p is the density of liquid and g is acceleration due to gravity

## The Attempt at a Solution

I know this above formula for height of liquid when the capillary is kept vertical .But don't know how to use it for the inclined capillary.

Can any1 help me out :)

Thanks for reading ^.^