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chawki
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Homework Statement
There is 0.76 kg of water in a well-insulated electric kettle. The water is being heated by a 41Ohms resistor that is connected to a voltage of 230 V.
The specific heat of water is 4190 J/(kgoC).
Homework Equations
How short is the time needed for the temperature of the water to rise by 15 C ?
The Attempt at a Solution
P=E/t
P=V2/R
P=2302/41
P=1290.24 watt
Q=m*Cp*delta T
Q=0.76*4190*15
Q=47766 J
Is Q here same as E ?
P=Q/t ----> t=Q/P
t=47766/1290.24
t=37.02 s ?