A cliff diver takes off horizontally from a cliff face 26.5 metres above the surface of the water. In the course of his flight, he travels 8 metres forwards, of which all but the last 1.5 metres of horizontal motion is above rock. In other words, he travels 6.5 metres in the air horizontally, before he falls and travels the remaining 1.5 metres. Questions: 1) How long is he in the air? s = 1/2 (g) (t^2), so time =2.3 seconds 2) How long is he OVER the water during the flight? I assume this is asking how long he travels at the 6.5 metres? I have no idea what equation to use or where to start - all i know is that the answer is 0.44 seconds...HELP!