How Does Water Pressure Change with Depth and Altitude?

In summary, the pressure increases by 439.4 kPa when going 34.5 m below the surface and decreases by 392.4 kPa when going 36 m above the surface. To calculate the first case, you can subtract the initial pressure of 106 kPa from the final pressure of 439.4 kPa. As for the second case, you can calculate the pressure at the surface using the equation P = ρgh, with the given density and height of 36 m, and then subtract it from the initial pressure to find the pressure decrease.
  • #1
Devin Longo
11
0

Homework Statement


At the surface of a freshwater lake the pressure is 106 kPa. (a) What is the pressure increase in going 34.5 m below the surface? (b) What is the approximate pressure decrease in going 36 m above the surface? Air at 20°C has density of 1.2 kg/m3.


Homework Equations


Ph20 = pgh
Pabs = Ph20 + Patm




The Attempt at a Solution



I calculated both equations and got 439.4 kPa. I then subtracted 106 from 439.4 to get number one, but it doesn't work! How can I calculate number one? Also, I don't know where to begin for 2!
 
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  • #2
The pressure change in both cases can be calculated via ΔP = ρgΔh.
 
  • #3


I would first clarify what type of pressure is being referred to in the problem. Based on the given information, it seems that the pressure at the surface of the lake is the absolute pressure, which includes the pressure from the water and the atmosphere. The pressure increase and decrease being asked for in the problem would then be the gauge pressure, which is the difference between the absolute pressure and the atmospheric pressure.

For part (a), the pressure increase in going 34.5 m below the surface can be calculated using the equation P = ρgh, where P is the pressure, ρ is the density of water (1000 kg/m3 for freshwater), g is the acceleration due to gravity (9.8 m/s2), and h is the depth. Plugging in the given values, we get P = (1000 kg/m3)(9.8 m/s2)(34.5 m) = 33900 Pa = 33.9 kPa. This is the gauge pressure, so to get the absolute pressure, we need to add the atmospheric pressure of 106 kPa. Therefore, the absolute pressure at a depth of 34.5 m is 139.9 kPa.

For part (b), the pressure decrease in going 36 m above the surface can be calculated using the same equation. However, in this case, the depth would be negative since we are going above the surface. So P = (1000 kg/m3)(9.8 m/s2)(-36 m) = -35280 Pa = -35.3 kPa. Again, this is the gauge pressure, so to get the absolute pressure, we add the atmospheric pressure of 106 kPa. Therefore, the absolute pressure at a height of 36 m above the surface is 70.7 kPa.

In summary, the absolute pressure at a depth of 34.5 m below the surface is 139.9 kPa and the absolute pressure at a height of 36 m above the surface is 70.7 kPa.
 

What is water pressure?

Water pressure is the force exerted by the weight of water in a body of water, such as a lake, on an object or surface at a certain depth.

How is water pressure measured?

Water pressure is typically measured in units of force per unit area, such as pounds per square inch (psi) or newtons per square meter (N/m²).

What factors affect water pressure in a lake?

The two main factors that affect water pressure in a lake are depth and density. The deeper the water, the greater the pressure due to the weight of the water above. Similarly, denser water, such as saltwater, will exert more pressure than less dense water, such as freshwater.

How does water pressure change with depth in a lake?

As depth increases in a lake, water pressure also increases. This is because the weight of the water above increases, creating more pressure on objects or surfaces at lower depths.

What are the practical applications of understanding water pressure in a lake?

Understanding water pressure in a lake is important for various applications such as diving, engineering, and environmental studies. It can also help in predicting changes in water level and potential hazards, such as flooding or landslides.

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