Suppose you adjust your garden hose nozzle for a hard stream of water. You point the nozzle vertically upward at a height of 1.5m above the ground. When you quickly move away from the vertical you hear the water striking the ground next to you for another 2.0s. What is the water speed as it leaves the nozzle? What I know/don't know: t (overall Time) = 2.0 Total distance = d2 +d1 +1.5m and that d2 = d1 +1.5m Event 1 Initial velocity = ? Final velocity = 0 m/s a= -9.80 m/s^2 Event 2 Initial velocity = 0 m/s Final velocity = ? a= -9.80 m/s^2 I'm not sure how to proceed. I suspect I need a subsitution - may be time and distance? Any help is appreciated!