1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Water speed through a pipe

  1. Apr 15, 2010 #1
    1. The problem statement, all variables and given/known data

    Water with pressure of 120 kPa is flowing through a rectangular pipe with velocity 1.9 m/s. At one point, the pipe narrows to one half of its original diameter. What is the velocity of the water at this narrower point? What is the pressure?

    2. Relevant equations

    v1A1 = v2A2?
    P = F/A

    3. The attempt at a solution

    I figured the pressure was irrelevant to figuring out the velocity in this equation, since water is basically incompressible. So, I just established v2 as the unknown variable...

    1.9 m/s * A = v2 * A/2

    (1.9 m/s * A)/(A/2) = v2

    v2 = 3.8 m/s

    For the pressure, I said that no change in energy is going to occur, so there's not going to be any change in force either...

    120 = F/A
    P2 = (F/.5A)

    .5P2 = F/A
    .5P2 = 120
    P2 = 60 kPa
  2. jcsd
  3. Apr 15, 2010 #2
    I think your answer to the first part is right. However, as the pipe narrows, the area halves, and the energy remains the same. Pressure is the same as energy per unit volume (J/m^3), so if energy remains the same, I don't think the force can be the same.
    I would use Bernouilli's equation:
    P_1 + 0.5p*v_1^2 = P_2 + 0.5p*v_2^2
    where p is the density of water (about 1000 kg/m^3)
    I may be wrong on this, but this is what I think.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook