1. The problem statement, all variables and given/known data A waterfall is 85ft high, and 3000 cubic ft/sec flow over it driving a water wheel connected to an electric generator. If the overall efficiency is 22%, how many kilowatts does the generator develop? 2. Relevant equations density of water =1000kg/cubic meter P.E. = mgh weight=density*g*volume 3. The attempt at a solution Firstly convert to SI units. 85ft = 25.91m 3000 cubicft/sec = 914.4 cubic meter/sec weight of the water being applied = (1000)(9.81)(914.4) = 8.97 MN P.E.=(8.97 MN)(25.91m) =232.42 MJ power in = 232.42 MJ /1sec = 232.42 megawatts eff =0.22 0.22 = POUT/232.42 MW Are my steps correct?