The electronic flash attachment for a camera contains a capacitor for storing the energy used to produce the flash. In one such unit, the potential difference between the plates of a 765 µF capacitor is 345 V.(adsbygoogle = window.adsbygoogle || []).push({});

(a) Determine the energy that is used to produce the flash in this unit.

Using the formula:

Energy = .5C(V^2) i found the energy to be 45.527 J

(b) Assuming that the flash lasts for 5.0 10-3 s, find the effective power or "wattage" of the flash.

I can not find a formula to convert the given information into wattage however.

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# Homework Help: Watt conversion question

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