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## Homework Statement

Suppose a hydrogen atom is in the [tex]2s[/tex] stat, with its wav function given by:

[tex]\psi_2_s (r) = \frac{1}{4\sqrt(2\pi a_o^\frac{3}{2})} (2-\frac{r}{a_o}) e^(-\frac{r}{2a_o})[/tex]

Taking [tex]r = a_o[/tex], calculate [tex]\psi_2_s (a_o)[/tex]

## Homework Equations

## The Attempt at a Solution

Since [tex]r=a_o=0.0529 nm[/tex], I get [tex]\frac{1.57*10^(14)}{ m^3}[/tex]

Now, my question is "what is the meaning of this value?