# Wave Function for Hydrogen

## Homework Statement

Suppose a hydrogen atom is in the $$2s$$ stat, with its wav function given by:

$$\psi_2_s (r) = \frac{1}{4\sqrt(2\pi a_o^\frac{3}{2})} (2-\frac{r}{a_o}) e^(-\frac{r}{2a_o})$$

Taking $$r = a_o$$, calculate $$\psi_2_s (a_o)$$

## The Attempt at a Solution

Since $$r=a_o=0.0529 nm$$, I get $$\frac{1.57*10^(14)}{ m^3}$$

Now, my question is "what is the meaning of this value?

## The Attempt at a Solution

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Redbelly98
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