Wave Function for Hydrogen

  • Thread starter jg370
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Homework Statement



Suppose a hydrogen atom is in the [tex]2s[/tex] stat, with its wav function given by:

[tex]\psi_2_s (r) = \frac{1}{4\sqrt(2\pi a_o^\frac{3}{2})} (2-\frac{r}{a_o}) e^(-\frac{r}{2a_o})[/tex]

Taking [tex]r = a_o[/tex], calculate [tex]\psi_2_s (a_o)[/tex]

Homework Equations




The Attempt at a Solution



Since [tex]r=a_o=0.0529 nm[/tex], I get [tex]\frac{1.57*10^(14)}{ m^3}[/tex]

Now, my question is "what is the meaning of this value?

Homework Statement





Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
Redbelly98
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Well, the units of a 3-D wave function should have m3/2 in the denominator (i.e. the units are m-3/2).

I'm not sure people actually ascribe physical meaning to the value of a wavefunction. I think of wavefunctions as a calculational tool in determining observable quantities such as position, momentum, energy, etc. QM is all about measurable quantities or observables.

Hope that helps.
 

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