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Wave function of a electron

  1. Apr 22, 2007 #1

    Lee

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    1. The problem statement, all variables and given/known data
    phi(r,0)=1/rt(2)(phi1+ph2)

    What is phi(r,t)?


    2. Relevant equations



    3. The attempt at a solution

    Is this simply a case of introducing a phase constant to the eqn. So:

    phi(r,t)=1/rt(2)(phi1+phi2)e^i(theta)t

    or do we need to modify phi1 and phi2.
     
  2. jcsd
  3. Apr 22, 2007 #2

    Meir Achuz

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    phi1 exp(-iE_1 t/hbar)+ same for 2.
     
  4. Apr 22, 2007 #3

    Lee

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    Oh, sorry.

    phi1=Aexp(-r/ao)
    phi2=B(1-r/ao)e(-r/2ao)

    where ao is the Bohr radius.

    As given by the question.

    So can I take the Energy of each wave function (that I have already calculated) and apply the above substitution?
     
  5. Apr 23, 2007 #4

    Lee

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    Can any give me some clarification.
     
  6. Apr 24, 2007 #5

    Meir Achuz

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    Yes, just multiply each phi by exp{-iEt/hbar} and add.
     
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