The following is a "ooze" wafve function:(adsbygoogle = window.adsbygoogle || []).push({});

[tex]\Psi_{ooze} (x,t)=\frac{1}{K} \left( \Psi_1 + \Psi_2+...+\Psi_{1000} \right) [/tex]

1. I am to find the value of K, but I dont even know what it represents. Is K the coefficent to normalize the probablity to 1?

2. Probability where energy [tex] E_q [/tex] can be observed?

[tex] E_n = \frac{n^2 \pi^2 \hbar^2}{2mL^2} [/tex]

[tex] \sum_{n=1}^q \frac{n^2 \pi^2 \hbar^2}{2mL^2} [/tex]

[tex] \frac{ \pi^2 \hbar^2}{2mL^2} \sum_{n=1}^q n^2 [/tex]

3. Then I am to find the average energy predicted to be observed. I am not sure what this even means. I am guessing: [tex] E_{avg} = \frac{n^2 \pi^2 \hbar^2}{2nmL^2} [/tex] ??

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# Homework Help: Wave functions

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